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Commit 2e70b8c6 authored by Chris Wilson's avatar Chris Wilson
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drm/i915/execlists: Relax the locked clear_bit(IRQ_EXECLIST)



We only need to care about the ordering of the clearing of the bit with
the uncached CSB read in order to correctly detect a new interrupt
before the read completes. The uncached read itself acts as a full
memory barrier, so we do not need to enforce another in the form of a
locked clear_bit.

v2: Clarify why the split and unlocked test/clear is harmless.

Signed-off-by: default avatarChris Wilson <chris@chris-wilson.co.uk>
Cc: Tvrtko Ursulin <tvrtko.ursulin@intel.com>
Link: http://patchwork.freedesktop.org/patch/msgid/20170323134803.10418-1-chris@chris-wilson.co.uk


Reviewed-by: default avatarTvrtko Ursulin <tvrtko.ursulin@intel.com>
parent 292889e1
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+11 −1
Original line number Diff line number Diff line
@@ -540,7 +540,17 @@ static void intel_lrc_irq_handler(unsigned long data)
			dev_priv->regs + i915_mmio_reg_offset(RING_CONTEXT_STATUS_BUF_LO(engine, 0));
		unsigned int csb, head, tail;

		clear_bit(ENGINE_IRQ_EXECLIST, &engine->irq_posted);
		/* The write will be ordered by the uncached read (itself
		 * a memory barrier), so we do not need another in the form
		 * of a locked instruction. The race between the interrupt
		 * handler and the split test/clear is harmless as we order
		 * our clear before the CSB read. If the interrupt arrived
		 * first between the test and the clear, we read the updated
		 * CSB and clear the bit. If the interrupt arrives as we read
		 * the CSB or later (i.e. after we had cleared the bit) the bit
		 * is set and we do a new loop.
		 */
		__clear_bit(ENGINE_IRQ_EXECLIST, &engine->irq_posted);
		csb = readl(csb_mmio);
		head = GEN8_CSB_READ_PTR(csb);
		tail = GEN8_CSB_WRITE_PTR(csb);