+6
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It is typical to pass error to callers like following;
if (!result) {
return Error() << result.error();
}
To transfer errno(or ResultError#code()), Error defines a specialization
operator<<(const ResultError&).
This change fixes so that ResultError is properly handled
Bug: 132145659
Test: atest libbase_test
Change-Id: Ib35457da2d4b923d8e652c54ac510a75546cf918