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Commit 375d18f7 authored by Grzegorz Kołodziejczyk's avatar Grzegorz Kołodziejczyk
Browse files

le_audio: Don't expose already exposed LE Audio active device 

Single LE Audio device may be represented as two separate device: input
and output for AudioManager. Since LE Audio serice is registered to add
device in static way it gets calls when input device is add and output
device is add. There is no need to expose twice that the same Bluetooth
device is active.

Tag: #feature
Bug: 271407426
Test: atest GoogleBluetoothInstrumentationTests
Change-Id: I59061171c9501da074a9e24528f9f6bc99174d0c
parent 6b5fcd75

android/app/src/com/android/bluetooth/le_audio/LeAudioService.java

+7 −0
Original line number Diff line number Diff line
@@ -116,6 +116,7 @@ public class LeAudioService extends ProfileService { 
    private HandlerThread mStateMachinesThread;

    private volatile BluetoothDevice mActiveAudioOutDevice;

    private volatile BluetoothDevice mActiveAudioInDevice;

    private BluetoothDevice mExposedActiveDevice;

    private LeAudioCodecConfig mLeAudioCodecConfig;

    private final Object mGroupLock = new Object();

    ServiceFactory mServiceFactory = new ServiceFactory();
@@ -1115,6 +1116,11 @@ public class LeAudioService extends ProfileService { 
                byte[] addressBytes = Utils.getBytesFromAddress(address);

                BluetoothDevice device = mAdapterService.getDeviceFromByte(addressBytes);



                /* Don't expose already exposed active device */

                if (device.equals(mExposedActiveDevice)) {

                    return;

                }



                if (DBG) {

                    Log.d(TAG, " onAudioDevicesAdded: " + device + ", device type: "

                            + deviceInfo.getType() + ", isSink: " + deviceInfo.isSink()
@@ -1129,6 +1135,7 @@ public class LeAudioService extends ProfileService { 
                    continue;

                }



                mExposedActiveDevice = device;

                notifyActiveDeviceChanged(device);

                return;

            }