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Commit bd45cf58 authored by Louis Chang's avatar Louis Chang
Browse files

Do not delay the event if the focused input target is the same 

The a11y service requests window focus every time while performing
an a11y action, which also notifies a pointer outside event. Since the
a11y action is to start an activity and the pointer outside event
that was postponed, the caller app task was unexpectedly be brought
to front after the activity launch.

Bug: 356080250
Test: enable talkback and follow the steps on the bug
Flag: EXEMPT bugfix
Change-Id: Ibdb6e8e977540aab1df5e61f33a1bdc28c82d9c0
parent b4eca62f

services/core/java/com/android/server/wm/WindowManagerService.java

+2 −1
Original line number Diff line number Diff line
@@ -9037,7 +9037,8 @@ public class WindowManagerService extends IWindowManager.Stub 
        // Otherwise, handle the touch-outside event directly.

        final WindowState w = t.getWindowState();

        final ActivityRecord activity = w != null ? w.getActivityRecord() : null;

        if (activity != null && activity.isEmbedded()

        if (mFocusedInputTarget != t && mFocusedInputTarget != null

                && activity != null && activity.isEmbedded()

                && activity.getTaskFragment().getAdjacentTaskFragment() != null) {

            mPointerDownOutsideFocusRunnable = () -> handlePointerDownOutsideFocus(t);

            mH.postDelayed(mPointerDownOutsideFocusRunnable, POINTER_DOWN_OUTSIDE_FOCUS_TIMEOUT_MS);