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Bug: 369619160 Flag: NONE - private API for debugging When transfering bitmap mId from sending side to receiving side, a same bitmap could be sent multiple times, which ends up with multiple bitmaps on the receiving end having the same mId. To keep mId unique while not losing the track of where the bitmap was originated from, we keep the source mId in a separate source field, and Bitmap.getSource()/Bitmap.setSource() to retrieve and specify the source bitmap. Change-Id: Ic85a0e8324fc0b1bf03b5ed8c1358b8449c00d49