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Commit 2e2cd8ba authored by Jesper Nilsson's avatar Jesper Nilsson Committed by Linus Torvalds
Browse files

CRISv10 memset library add lineendings to asm 



Add \n\ at end of lines inside asm statement to avoid warning.

No change except adding \n\ to end of line and correcting
whitespace has been done.
Removes warning about multi-line string literals when compiling
arch/cris/arch-v10/lib/memset.c

Signed-off-by: default avatarJesper Nilsson <jesper.nilsson@axis.com>
Cc: Mikael Starvik <mikael.starvik@axis.com>
Signed-off-by: default avatarAndrew Morton <akpm@linux-foundation.org>
Signed-off-by: default avatarLinus Torvalds <torvalds@linux-foundation.org>
parent 341ac6e4

arch/cris/arch-v10/lib/memset.c

+41 −41
Original line number Diff line number Diff line
@@ -110,43 +110,43 @@ void *memset(void *pdst, 
      If you want to check that the allocation was right; then

      check the equalities in the first comment.  It should say

      "r13=r13, r12=r12, r11=r11" */

    __asm__ volatile ("

        ;; Check that the following is true (same register names on

        ;; both sides of equal sign, as in r8=r8):

        ;; %0=r13, %1=r12, %4=r11

        ;;

	;; Save the registers we'll clobber in the movem process

	;; on the stack.  Don't mention them to gcc, it will only be

	;; upset.

	subq 	11*4,$sp

        movem   $r10,[$sp]



        move.d  $r11,$r0

        move.d  $r11,$r1

        move.d  $r11,$r2

        move.d  $r11,$r3

        move.d  $r11,$r4

        move.d  $r11,$r5

        move.d  $r11,$r6

        move.d  $r11,$r7

        move.d  $r11,$r8

        move.d  $r11,$r9

        move.d  $r11,$r10



        ;; Now we've got this:

	;; r13 - dst

	;; r12 - n

	

        ;; Update n for the first loop

        subq    12*4,$r12

0:

        subq   12*4,$r12

        bge     0b

	movem	$r11,[$r13+]



        addq   12*4,$r12  ;; compensate for last loop underflowing n



	;; Restore registers from stack

    __asm__ volatile ("\n\

	;; Check that the following is true (same register names on	\n\

	;; both sides of equal sign, as in r8=r8):			\n\

	;; %0=r13, %1=r12, %4=r11					\n\

	;;								\n\

	;; Save the registers we'll clobber in the movem process	\n\

	;; on the stack.  Don't mention them to gcc, it will only be	\n\

	;; upset.							\n\

	subq	11*4,$sp						\n\

	movem	$r10,[$sp]						\n\

									\n\

	move.d	$r11,$r0						\n\

	move.d	$r11,$r1						\n\

	move.d	$r11,$r2						\n\

	move.d	$r11,$r3						\n\

	move.d	$r11,$r4						\n\

	move.d	$r11,$r5						\n\

	move.d	$r11,$r6						\n\

	move.d	$r11,$r7						\n\

	move.d	$r11,$r8						\n\

	move.d	$r11,$r9						\n\

	move.d	$r11,$r10						\n\

									\n\

	;; Now we've got this:						\n\

	;; r13 - dst							\n\

	;; r12 - n							\n\

									\n\

	;; Update n for the first loop					\n\

	subq	12*4,$r12						\n\

0:									\n\

	subq	12*4,$r12						\n\

	bge	0b							\n\

	movem	$r11,[$r13+]						\n\

									\n\

	addq	12*4,$r12 ;; compensate for last loop underflowing n	\n\

									\n\

	;; Restore registers from stack					\n\

	movem	[$sp+],$r10"



     /* Outputs */ : "=r" (dst), "=r" (n)