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Commit 58d6c2d7 authored by Peter Zijlstra's avatar Peter Zijlstra Committed by Ingo Molnar
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sched: rt-group: optimize dequeue_rt_stack



Now that the group hierarchy can have an arbitrary depth the O(n^2) nature
of RT task dequeues will really hurt. Optimize this by providing space to
store the tree path, so we can walk it the other way.

Signed-off-by: default avatarPeter Zijlstra <a.p.zijlstra@chello.nl>
Signed-off-by: default avatarIngo Molnar <mingo@elte.hu>
parent d19ca308
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+1 −0
Original line number Diff line number Diff line
@@ -1005,6 +1005,7 @@ struct sched_rt_entity {
	unsigned long timeout;
	int nr_cpus_allowed;

	struct sched_rt_entity *back;
#ifdef CONFIG_RT_GROUP_SCHED
	struct sched_rt_entity	*parent;
	/* rq on which this entity is (to be) queued: */
+11 −16
Original line number Diff line number Diff line
@@ -479,26 +479,21 @@ static void dequeue_rt_entity(struct sched_rt_entity *rt_se)
/*
 * Because the prio of an upper entry depends on the lower
 * entries, we must remove entries top - down.
 *
 * XXX: O(1/2 h^2) because we can only walk up, not down the chain.
 */
static void dequeue_rt_stack(struct task_struct *p)
{
	struct sched_rt_entity *rt_se, *top_se;
	struct sched_rt_entity *rt_se, *back = NULL;

	/*
	 * dequeue all, top - down.
	 */
	do {
	rt_se = &p->rt;
		top_se = NULL;
	for_each_sched_rt_entity(rt_se) {
		rt_se->back = back;
		back = rt_se;
	}

	for (rt_se = back; rt_se; rt_se = rt_se->back) {
		if (on_rt_rq(rt_se))
				top_se = rt_se;
			dequeue_rt_entity(rt_se);
	}
		if (top_se)
			dequeue_rt_entity(top_se);
	} while (top_se);
}

/*