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Commit f171d4d7 authored by Artem Bityutskiy's avatar Artem Bityutskiy
Browse files

UBIFS: fix division by zero



If fanout is 3, we have division by zero in
'ubifs_read_superblock()':

divide error: 0000 [#1] PREEMPT SMP

Pid: 28744, comm: mount Not tainted (2.6.27-rc4-ubifs-2.6 #23)
EIP: 0060:[<f8f9e3ef>] EFLAGS: 00010202 CPU: 0
EIP is at ubifs_reported_space+0x2d/0x69 [ubifs]
EAX: 00000000 EBX: 00000000 ECX: 00000000 EDX: 00000000
ESI: 00000000 EDI: f0ae64b0 EBP: f1f9fcf4 ESP: f1f9fce0
 DS: 007b ES: 007b FS: 00d8 GS: 0033 SS: 0068

Signed-off-by: default avatarArtem Bityutskiy <Artem.Bityutskiy@nokia.com>
parent 7c7cbadf
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+7 −6
Original line number Diff line number Diff line
@@ -723,24 +723,25 @@ void ubifs_release_dirty_inode_budget(struct ubifs_info *c,
 */
long long ubifs_reported_space(const struct ubifs_info *c, uint64_t free)
{
	int divisor, factor;
	int divisor, factor, f;

	/*
	 * Reported space size is @free * X, where X is UBIFS block size
	 * divided by UBIFS block size + all overhead one data block
	 * introduces. The overhead is the node header + indexing overhead.
	 *
	 * Indexing overhead is calculations are based on the following
	 * formula: I = N/(f - 1) + 1, where I - number of indexing nodes, N -
	 * number of data nodes, f - fanout. Because effective UBIFS fanout is
	 * twice as less than maximum fanout, we assume that each data node
	 * Indexing overhead calculations are based on the following formula:
	 * I = N/(f - 1) + 1, where I - number of indexing nodes, N - number
	 * of data nodes, f - fanout. Because effective UBIFS fanout is twice
	 * as less than maximum fanout, we assume that each data node
	 * introduces 3 * @c->max_idx_node_sz / (@c->fanout/2 - 1) bytes.
	 * Note, the multiplier 3 is because UBIFS reseves thrice as more space
	 * for the index.
	 */
	f = c->fanout > 3 ? c->fanout >> 1 : 2;
	factor = UBIFS_BLOCK_SIZE;
	divisor = UBIFS_MAX_DATA_NODE_SZ;
	divisor += (c->max_idx_node_sz * 3) / ((c->fanout >> 1) - 1);
	divisor += (c->max_idx_node_sz * 3) / (f - 1);
	free *= factor;
	do_div(free, divisor);
	return free;