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Commit d101f649 authored by Ivo van Doorn's avatar Ivo van Doorn Committed by John W. Linville
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rt2x00: Fix ieee80211 payload alignment



As Johannes Berg indicated, the NET_IP_ALIGN doesn't
need to be used for ieee80211 frames. This means we
can simplify the alignment calculation to just
use the result of the header size modulus 4 as frame
alignment.

Furthermore we shouldn't use NET_IP_ALIGN in rt2x00usb
because it could be 0 on some architectures and we absolutely
need to have 2 bytes reserved for possible aligning.

Signed-off-by: default avatarIvo van <Doorn&lt;IvDoorn@gmail.com>
Signed-off-by: default avatarJohn W. Linville <linville@tuxdriver.com>
parent a38db5b6
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+1 −1
Original line number Diff line number Diff line
@@ -149,7 +149,7 @@ void rt2x00pci_rxdone(struct rt2x00_dev *rt2x00dev)
		 * The data behind the ieee80211 header must be
		 * aligned on a 4 byte boundary.
		 */
		align = NET_IP_ALIGN + (2 * (header_size % 4 == 0));
		align = header_size % 4;

		/*
		 * Allocate the sk_buffer, initialize it and copy
+9 −2
Original line number Diff line number Diff line
@@ -245,13 +245,20 @@ static void rt2x00usb_interrupt_rxdone(struct urb *urb)
	 * Allocate a new sk buffer to replace the current one.
	 * If allocation fails, we should drop the current frame
	 * so we can recycle the existing sk buffer for the new frame.
	 * As alignment we use 2 and not NET_IP_ALIGN because we need
	 * to be sure we have 2 bytes room in the head. (NET_IP_ALIGN
	 * can be 0 on some hardware). We use these 2 bytes for frame
	 * alignment later, we assume that the chance that
	 * header_size % 4 == 2 is bigger then header_size % 2 == 0
	 * and thus optimize alignment by reserving the 2 bytes in
	 * advance.
	 */
	frame_size = entry->ring->data_size + entry->ring->desc_size;
	skb = dev_alloc_skb(frame_size + NET_IP_ALIGN);
	skb = dev_alloc_skb(frame_size + 2);
	if (!skb)
		goto skip_entry;

	skb_reserve(skb, NET_IP_ALIGN);
	skb_reserve(skb, 2);
	skb_put(skb, frame_size);

	/*