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Commit 48002bd5 authored by Heiko Carstens's avatar Heiko Carstens Committed by Martin Schwidefsky
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s390/bitops: remove 31 bit related comments

parent e4165dcb
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+12 −19
Original line number Diff line number Diff line
@@ -11,30 +11,25 @@
 * big-endian system because, unlike little endian, the number of each
 * bit depends on the word size.
 *
 * The bitop functions are defined to work on unsigned longs, so for an
 * s390x system the bits end up numbered:
 * The bitop functions are defined to work on unsigned longs, so the bits
 * end up numbered:
 *   |63..............0|127............64|191...........128|255...........192|
 * and on s390:
 *   |31.....0|63....32|95....64|127...96|159..128|191..160|223..192|255..224|
 *
 * There are a few little-endian macros used mostly for filesystem
 * bitmaps, these work on similar bit arrays layouts, but
 * byte-oriented:
 * bitmaps, these work on similar bit array layouts, but byte-oriented:
 *   |7...0|15...8|23...16|31...24|39...32|47...40|55...48|63...56|
 *
 * The main difference is that bit 3-5 (64b) or 3-4 (32b) in the bit
 * number field needs to be reversed compared to the big-endian bit
 * fields. This can be achieved by XOR with 0x38 (64b) or 0x18 (32b).
 * The main difference is that bit 3-5 in the bit number field needs to be
 * reversed compared to the big-endian bit fields. This can be achieved by
 * XOR with 0x38.
 *
 * We also have special functions which work with an MSB0 encoding:
 * on an s390x system the bits are numbered:
 * We also have special functions which work with an MSB0 encoding.
 * The bits are numbered:
 *   |0..............63|64............127|128...........191|192...........255|
 * and on s390:
 *   |0.....31|32....63|64....95|96...127|128..159|160..191|192..223|224..255|
 *
 * The main difference is that bit 0-63 (64b) or 0-31 (32b) in the bit
 * number field needs to be reversed compared to the LSB0 encoded bit
 * fields. This can be achieved by XOR with 0x3f (64b) or 0x1f (32b).
 * The main difference is that bit 0-63 in the bit number field needs to be
 * reversed compared to the LSB0 encoded bit fields. This can be achieved by
 * XOR with 0x3f.
 *
 */

@@ -299,10 +294,8 @@ static inline void __clear_bit_unlock(unsigned long nr,

/*
 * Functions which use MSB0 bit numbering.
 * On an s390x system the bits are numbered:
 * The bits are numbered:
 *   |0..............63|64............127|128...........191|192...........255|
 * and on s390:
 *   |0.....31|32....63|64....95|96...127|128..159|160..191|192..223|224..255|
 */
unsigned long find_first_bit_inv(const unsigned long *addr, unsigned long size);
unsigned long find_next_bit_inv(const unsigned long *addr, unsigned long size,
+1 −3
Original line number Diff line number Diff line
/*
 * MSB0 numbered special bitops handling.
 *
 * On s390x the bits are numbered:
 * The bits are numbered:
 *   |0..............63|64............127|128...........191|192...........255|
 * and on s390:
 *   |0.....31|32....63|64....95|96...127|128..159|160..191|192..223|224..255|
 *
 * The reason for this bit numbering is the fact that the hardware sets bits
 * in a bitmap starting at bit 0 (MSB) and we don't want to scan the bitmap