crc32: move long comment about crc32 fundamentals to Documentation/

	- info on CPU_IDLE, CPU idle state management subsystem.

cputopology.txt

	- documentation on how CPU topology info is exported via sysfs.

crc32.txt

	- brief tutorial on CRC computation

cris/

	- directory with info about Linux on CRIS architecture.

crypto/

A brief CRC tutorial.

A CRC is a long-division remainder.  You add the CRC to the message,

and the whole thing (message+CRC) is a multiple of the given

CRC polynomial.  To check the CRC, you can either check that the

CRC matches the recomputed value, *or* you can check that the

remainder computed on the message+CRC is 0.  This latter approach

is used by a lot of hardware implementations, and is why so many

protocols put the end-of-frame flag after the CRC.

It's actually the same long division you learned in school, except that

- We're working in binary, so the digits are only 0 and 1, and

- When dividing polynomials, there are no carries.  Rather than add and

  subtract, we just xor.  Thus, we tend to get a bit sloppy about

  the difference between adding and subtracting.

Like all division, the remainder is always smaller than the divisor.

To produce a 32-bit CRC, the divisor is actually a 33-bit CRC polynomial.

Since it's 33 bits long, bit 32 is always going to be set, so usually the

CRC is written in hex with the most significant bit omitted.  (If you're

familiar with the IEEE 754 floating-point format, it's the same idea.)

Note that a CRC is computed over a string of *bits*, so you have

to decide on the endianness of the bits within each byte.  To get

the best error-detecting properties, this should correspond to the

order they're actually sent.  For example, standard RS-232 serial is

little-endian; the most significant bit (sometimes used for parity)

is sent last.  And when appending a CRC word to a message, you should

do it in the right order, matching the endianness.

Just like with ordinary division, you proceed one digit (bit) at a time.

Each step of the division you take one more digit (bit) of the dividend

and append it to the current remainder.  Then you figure out the

appropriate multiple of the divisor to subtract to being the remainder

back into range.  In binary, this is easy - it has to be either 0 or 1,

and to make the XOR cancel, it's just a copy of bit 32 of the remainder.

When computing a CRC, we don't care about the quotient, so we can

throw the quotient bit away, but subtract the appropriate multiple of

the polynomial from the remainder and we're back to where we started,

ready to process the next bit.

A big-endian CRC written this way would be coded like:

for (i = 0; i < input_bits; i++) {

	multiple = remainder & 0x80000000 ? CRCPOLY : 0;

	remainder = (remainder << 1 | next_input_bit()) ^ multiple;

}

Notice how, to get at bit 32 of the shifted remainder, we look

at bit 31 of the remainder *before* shifting it.

But also notice how the next_input_bit() bits we're shifting into

the remainder don't actually affect any decision-making until

32 bits later.  Thus, the first 32 cycles of this are pretty boring.

Also, to add the CRC to a message, we need a 32-bit-long hole for it at

the end, so we have to add 32 extra cycles shifting in zeros at the

end of every message,

These details lead to a standard trick: rearrange merging in the

next_input_bit() until the moment it's needed.  Then the first 32 cycles

can be precomputed, and merging in the final 32 zero bits to make room

for the CRC can be skipped entirely.  This changes the code to:

for (i = 0; i < input_bits; i++) {

	remainder ^= next_input_bit() << 31;

	multiple = (remainder & 0x80000000) ? CRCPOLY : 0;

	remainder = (remainder << 1) ^ multiple;

}

With this optimization, the little-endian code is particularly simple:

for (i = 0; i < input_bits; i++) {

	remainder ^= next_input_bit();

	multiple = (remainder & 1) ? CRCPOLY : 0;

	remainder = (remainder >> 1) ^ multiple;

}

The most significant coefficient of the remainder polynomial is stored

in the least significant bit of the binary "remainder" variable.

The other details of endianness have been hidden in CRCPOLY (which must

be bit-reversed) and next_input_bit().

As long as next_input_bit is returning the bits in a sensible order, we don't

*have* to wait until the last possible moment to merge in additional bits.

We can do it 8 bits at a time rather than 1 bit at a time:

for (i = 0; i < input_bytes; i++) {

	remainder ^= next_input_byte() << 24;

	for (j = 0; j < 8; j++) {

		multiple = (remainder & 0x80000000) ? CRCPOLY : 0;

		remainder = (remainder << 1) ^ multiple;

	}

}

Or in little-endian:

for (i = 0; i < input_bytes; i++) {

	remainder ^= next_input_byte();

	for (j = 0; j < 8; j++) {

		multiple = (remainder & 1) ? CRCPOLY : 0;

		remainder = (remainder >> 1) ^ multiple;

	}

}

If the input is a multiple of 32 bits, you can even XOR in a 32-bit

word at a time and increase the inner loop count to 32.

You can also mix and match the two loop styles, for example doing the

bulk of a message byte-at-a-time and adding bit-at-a-time processing

for any fractional bytes at the end.

To reduce the number of conditional branches, software commonly uses

the byte-at-a-time table method, popularized by Dilip V. Sarwate,

"Computation of Cyclic Redundancy Checks via Table Look-Up", Comm. ACM

v.31 no.8 (August 1998) p. 1008-1013.

Here, rather than just shifting one bit of the remainder to decide

in the correct multiple to subtract, we can shift a byte at a time.

This produces a 40-bit (rather than a 33-bit) intermediate remainder,

and the correct multiple of the polynomial to subtract is found using

a 256-entry lookup table indexed by the high 8 bits.

(The table entries are simply the CRC-32 of the given one-byte messages.)

When space is more constrained, smaller tables can be used, e.g. two

4-bit shifts followed by a lookup in a 16-entry table.

It is not practical to process much more than 8 bits at a time using this

technique, because tables larger than 256 entries use too much memory and,

more importantly, too much of the L1 cache.

To get higher software performance, a "slicing" technique can be used.

See "High Octane CRC Generation with the Intel Slicing-by-8 Algorithm",

ftp://download.intel.com/technology/comms/perfnet/download/slicing-by-8.pdf

This does not change the number of table lookups, but does increase

the parallelism.  With the classic Sarwate algorithm, each table lookup

must be completed before the index of the next can be computed.

A "slicing by 2" technique would shift the remainder 16 bits at a time,

producing a 48-bit intermediate remainder.  Rather than doing a single

lookup in a 65536-entry table, the two high bytes are looked up in

two different 256-entry tables.  Each contains the remainder required

to cancel out the corresponding byte.  The tables are different because the

polynomials to cancel are different.  One has non-zero coefficients from

x^32 to x^39, while the other goes from x^40 to x^47.

Since modern processors can handle many parallel memory operations, this

takes barely longer than a single table look-up and thus performs almost

twice as fast as the basic Sarwate algorithm.

This can be extended to "slicing by 4" using 4 256-entry tables.

Each step, 32 bits of data is fetched, XORed with the CRC, and the result

broken into bytes and looked up in the tables.  Because the 32-bit shift

leaves the low-order bits of the intermediate remainder zero, the

final CRC is simply the XOR of the 4 table look-ups.

But this still enforces sequential execution: a second group of table

look-ups cannot begin until the previous groups 4 table look-ups have all

been completed.  Thus, the processor's load/store unit is sometimes idle.

To make maximum use of the processor, "slicing by 8" performs 8 look-ups

in parallel.  Each step, the 32-bit CRC is shifted 64 bits and XORed

with 64 bits of input data.  What is important to note is that 4 of

those 8 bytes are simply copies of the input data; they do not depend

on the previous CRC at all.  Thus, those 4 table look-ups may commence

immediately, without waiting for the previous loop iteration.

By always having 4 loads in flight, a modern superscalar processor can

be kept busy and make full use of its L1 cache.

Two more details about CRC implementation in the real world:

Normally, appending zero bits to a message which is already a multiple

of a polynomial produces a larger multiple of that polynomial.  Thus,

a basic CRC will not detect appended zero bits (or bytes).  To enable

a CRC to detect this condition, it's common to invert the CRC before

appending it.  This makes the remainder of the message+crc come out not

as zero, but some fixed non-zero value.  (The CRC of the inversion

pattern, 0xffffffff.)

The same problem applies to zero bits prepended to the message, and a

similar solution is used.  Instead of starting the CRC computation with

a remainder of 0, an initial remainder of all ones is used.  As long as

you start the same way on decoding, it doesn't make a difference.

 * Version 2.  See the file COPYING for more details.

 */

/* see: Documentation/crc32.txt for a description of algorithms */

#include <linux/crc32.h>

#include <linux/kernel.h>

#include <linux/module.h>

EXPORT_SYMBOL(crc32_le);

EXPORT_SYMBOL(crc32_be);

/*

 * A brief CRC tutorial.

 *

 * A CRC is a long-division remainder.  You add the CRC to the message,

 * and the whole thing (message+CRC) is a multiple of the given

 * CRC polynomial.  To check the CRC, you can either check that the

 * CRC matches the recomputed value, *or* you can check that the

 * remainder computed on the message+CRC is 0.  This latter approach

 * is used by a lot of hardware implementations, and is why so many

 * protocols put the end-of-frame flag after the CRC.

 *

 * It's actually the same long division you learned in school, except that

 * - We're working in binary, so the digits are only 0 and 1, and

 * - When dividing polynomials, there are no carries.  Rather than add and

 *   subtract, we just xor.  Thus, we tend to get a bit sloppy about

 *   the difference between adding and subtracting.

 *

 * A 32-bit CRC polynomial is actually 33 bits long.  But since it's

 * 33 bits long, bit 32 is always going to be set, so usually the CRC

 * is written in hex with the most significant bit omitted.  (If you're

 * familiar with the IEEE 754 floating-point format, it's the same idea.)

 *

 * Note that a CRC is computed over a string of *bits*, so you have

 * to decide on the endianness of the bits within each byte.  To get

 * the best error-detecting properties, this should correspond to the

 * order they're actually sent.  For example, standard RS-232 serial is

 * little-endian; the most significant bit (sometimes used for parity)

 * is sent last.  And when appending a CRC word to a message, you should

 * do it in the right order, matching the endianness.

 *

 * Just like with ordinary division, the remainder is always smaller than

 * the divisor (the CRC polynomial) you're dividing by.  Each step of the

 * division, you take one more digit (bit) of the dividend and append it

 * to the current remainder.  Then you figure out the appropriate multiple

 * of the divisor to subtract to being the remainder back into range.

 * In binary, it's easy - it has to be either 0 or 1, and to make the

 * XOR cancel, it's just a copy of bit 32 of the remainder.

 *

 * When computing a CRC, we don't care about the quotient, so we can

 * throw the quotient bit away, but subtract the appropriate multiple of

 * the polynomial from the remainder and we're back to where we started,

 * ready to process the next bit.

 *

 * A big-endian CRC written this way would be coded like:

 * for (i = 0; i < input_bits; i++) {

 * 	multiple = remainder & 0x80000000 ? CRCPOLY : 0;

 * 	remainder = (remainder << 1 | next_input_bit()) ^ multiple;

 * }

 * Notice how, to get at bit 32 of the shifted remainder, we look

 * at bit 31 of the remainder *before* shifting it.

 *

 * But also notice how the next_input_bit() bits we're shifting into

 * the remainder don't actually affect any decision-making until

 * 32 bits later.  Thus, the first 32 cycles of this are pretty boring.

 * Also, to add the CRC to a message, we need a 32-bit-long hole for it at

 * the end, so we have to add 32 extra cycles shifting in zeros at the

 * end of every message,

 *

 * So the standard trick is to rearrage merging in the next_input_bit()

 * until the moment it's needed.  Then the first 32 cycles can be precomputed,

 * and merging in the final 32 zero bits to make room for the CRC can be

 * skipped entirely.

 * This changes the code to:

 * for (i = 0; i < input_bits; i++) {

 *      remainder ^= next_input_bit() << 31;

 * 	multiple = (remainder & 0x80000000) ? CRCPOLY : 0;

 * 	remainder = (remainder << 1) ^ multiple;

 * }

 * With this optimization, the little-endian code is simpler:

 * for (i = 0; i < input_bits; i++) {

 *      remainder ^= next_input_bit();

 * 	multiple = (remainder & 1) ? CRCPOLY : 0;

 * 	remainder = (remainder >> 1) ^ multiple;

 * }

 *

 * Note that the other details of endianness have been hidden in CRCPOLY

 * (which must be bit-reversed) and next_input_bit().

 *

 * However, as long as next_input_bit is returning the bits in a sensible

 * order, we can actually do the merging 8 or more bits at a time rather

 * than one bit at a time:

 * for (i = 0; i < input_bytes; i++) {

 * 	remainder ^= next_input_byte() << 24;

 * 	for (j = 0; j < 8; j++) {

 * 		multiple = (remainder & 0x80000000) ? CRCPOLY : 0;

 * 		remainder = (remainder << 1) ^ multiple;

 * 	}

 * }

 * Or in little-endian:

 * for (i = 0; i < input_bytes; i++) {

 * 	remainder ^= next_input_byte();

 * 	for (j = 0; j < 8; j++) {

 * 		multiple = (remainder & 1) ? CRCPOLY : 0;

 * 		remainder = (remainder << 1) ^ multiple;

 * 	}

 * }

 * If the input is a multiple of 32 bits, you can even XOR in a 32-bit

 * word at a time and increase the inner loop count to 32.

 *

 * You can also mix and match the two loop styles, for example doing the

 * bulk of a message byte-at-a-time and adding bit-at-a-time processing

 * for any fractional bytes at the end.

 *

 * The only remaining optimization is to the byte-at-a-time table method.

 * Here, rather than just shifting one bit of the remainder to decide

 * in the correct multiple to subtract, we can shift a byte at a time.

 * This produces a 40-bit (rather than a 33-bit) intermediate remainder,

 * but again the multiple of the polynomial to subtract depends only on

 * the high bits, the high 8 bits in this case.

 *

 * The multiple we need in that case is the low 32 bits of a 40-bit

 * value whose high 8 bits are given, and which is a multiple of the

 * generator polynomial.  This is simply the CRC-32 of the given

 * one-byte message.

 *

 * Two more details: normally, appending zero bits to a message which

 * is already a multiple of a polynomial produces a larger multiple of that

 * polynomial.  To enable a CRC to detect this condition, it's common to

 * invert the CRC before appending it.  This makes the remainder of the

 * message+crc come out not as zero, but some fixed non-zero value.

 *

 * The same problem applies to zero bits prepended to the message, and

 * a similar solution is used.  Instead of starting with a remainder of

 * 0, an initial remainder of all ones is used.  As long as you start

 * the same way on decoding, it doesn't make a difference.

 */

#ifdef UNITTEST

#include <stdlib.h>