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Commit bf4b85b0 authored by Nathan Lynch's avatar Nathan Lynch Committed by Paul Mackerras
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[PATCH] powerpc numa: Minor debugging code changes



Add debug statement for map_cpu_to_node; it's useful for cpu hotplug.

Clarify debug statement about not finding the numa reference points
property.

Don't print a meaningless associativity depth (-1) on non-numa systems.

Signed-off-by: default avatarNathan Lynch <nathanl@austin.ibm.com>
Signed-off-by: default avatarPaul Mackerras <paulus@samba.org>
parent c08888cf
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+5 −3
Original line number Original line Diff line number Diff line
@@ -133,6 +133,8 @@ static inline void map_cpu_to_node(int cpu, int node)
{
{
	numa_cpu_lookup_table[cpu] = node;
	numa_cpu_lookup_table[cpu] = node;


	dbg("adding cpu %d to node %d\n", cpu, node);

	if (!(cpu_isset(cpu, numa_cpumask_lookup_table[node])))
	if (!(cpu_isset(cpu, numa_cpumask_lookup_table[node])))
		cpu_set(cpu, numa_cpumask_lookup_table[node]);
		cpu_set(cpu, numa_cpumask_lookup_table[node]);
}
}
@@ -246,8 +248,7 @@ static int __init find_min_common_depth(void)
	if ((len >= 1) && ref_points) {
	if ((len >= 1) && ref_points) {
		depth = ref_points[1];
		depth = ref_points[1];
	} else {
	} else {
		dbg("WARNING: could not find NUMA "
		dbg("NUMA: ibm,associativity-reference-points not found.\n");
		    "associativity reference point\n");
		depth = -1;
		depth = -1;
	}
	}
	of_node_put(rtas_root);
	of_node_put(rtas_root);
@@ -385,10 +386,11 @@ static int __init parse_numa_properties(void)


	min_common_depth = find_min_common_depth();
	min_common_depth = find_min_common_depth();


	dbg("NUMA associativity depth for CPU/Memory: %d\n", min_common_depth);
	if (min_common_depth < 0)
	if (min_common_depth < 0)
		return min_common_depth;
		return min_common_depth;


	dbg("NUMA associativity depth for CPU/Memory: %d\n", min_common_depth);

	/*
	/*
	 * Even though we connect cpus to numa domains later in SMP init,
	 * Even though we connect cpus to numa domains later in SMP init,
	 * we need to know the maximum node id now. This is because each
	 * we need to know the maximum node id now. This is because each