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Commit 3ea8d440 authored by Rasmus Villemoes's avatar Rasmus Villemoes Committed by Linus Torvalds
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lib/vsprintf.c: eliminate duplicate hex string array



gcc doesn't merge or overlap const char[] objects with identical contents
(probably language lawyers would also insist that these things have
different addresses), but there's no reason to have the string
"0123456789ABCDEF" occur in multiple places.  hex_asc_upper is declared in
kernel.h and defined in lib/hexdump.c, which is unconditionally compiled
in.

Signed-off-by: default avatarRasmus Villemoes <linux@rasmusvillemoes.dk>
Cc: Peter Zijlstra <a.p.zijlstra@chello.nl>
Cc: Tejun Heo <tj@kernel.org>
Signed-off-by: default avatarAndrew Morton <akpm@linux-foundation.org>
Signed-off-by: default avatarLinus Torvalds <torvalds@linux-foundation.org>
parent e26c12c7
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+2 −5
Original line number Diff line number Diff line
@@ -383,9 +383,6 @@ static noinline_for_stack
char *number(char *buf, char *end, unsigned long long num,
	     struct printf_spec spec)
{
	/* we are called with base 8, 10 or 16, only, thus don't need "G..."  */
	static const char digits[16] = "0123456789ABCDEF"; /* "GHIJKLMNOPQRSTUVWXYZ"; */

	char tmp[3 * sizeof(num)];
	char sign;
	char locase;
@@ -422,7 +419,7 @@ char *number(char *buf, char *end, unsigned long long num,
	/* generate full string in tmp[], in reverse order */
	i = 0;
	if (num < spec.base)
		tmp[i++] = digits[num] | locase;
		tmp[i++] = hex_asc_upper[num] | locase;
	else if (spec.base != 10) { /* 8 or 16 */
		int mask = spec.base - 1;
		int shift = 3;
@@ -430,7 +427,7 @@ char *number(char *buf, char *end, unsigned long long num,
		if (spec.base == 16)
			shift = 4;
		do {
			tmp[i++] = (digits[((unsigned char)num) & mask] | locase);
			tmp[i++] = (hex_asc_upper[((unsigned char)num) & mask] | locase);
			num >>= shift;
		} while (num);
	} else { /* base 10 */