+29
−49
+2
−8
+11
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The cleanup path makes an effort to only perform an atomic read of the 64-bit completion address. However in the 32-bit case it does not matter if we read the upper-32 and lower-32 non-atomically because the upper-32 will always be zero. Signed-off-by:Maciej Sosnowski <maciej.sosnowski@intel.com> Signed-off-by:
Dan Williams <dan.j.williams@intel.com>